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	<title>Corey Charette (dot) com &#187; formula</title>
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	<link>http://www.coreycharette.com</link>
	<description>Welcome to my mind!</description>
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		<title>The lifespan of a balloon</title>
		<link>http://www.coreycharette.com/the-lifespan-of-a-balloon/</link>
		<comments>http://www.coreycharette.com/the-lifespan-of-a-balloon/#comments</comments>
		<pubDate>Fri, 21 Nov 2008 01:00:42 +0000</pubDate>
		<dc:creator>Corey Charette</dc:creator>
				<category><![CDATA[Life]]></category>
		<category><![CDATA[Uncategorized]]></category>
		<category><![CDATA[balloon]]></category>
		<category><![CDATA[children]]></category>
		<category><![CDATA[formula]]></category>
		<category><![CDATA[pop]]></category>

		<guid isPermaLink="false">http://www.coreycharette.com/?p=189</guid>
		<description><![CDATA[As I was at my son&#8217;s football banquet on Sunday, I was watching the kids running around with balloons hitting each other and having a good time. Then, I thought to myself: &#8220;How long will it be before one of them pops?&#8221;  Within a few minutes a loud BANG was heard throughout the hall. So, [...]]]></description>
			<content:encoded><![CDATA[<p>As I was at my son&#8217;s football banquet on Sunday, I was watching the kids running around with balloons hitting each other and having a good time.</p>
<p>Then, I thought to myself: &#8220;How long will it be before one of them pops?&#8221;  Within a few minutes a loud BANG was heard throughout the hall.</p>
<p>So, I sat down and tried to figure out how to determine how long it takes before one of the balloons pops.</p>
<p>Here&#8217;s my formula:</p>
<p><em>minutes til pop = (number of kids total &#8211; number of kids with balloons) x square footage of area they are playing in</em></p>
<p><em></em></p>
<p> <br />
Looking at this formula: the more kids in the group with balloons and the smaller the area they are playing it the higher chance of one of the balloons popping.</p>
<p>Of course, this hasn&#8217;t been verified with scientific study, but any observed eye can attest to this theory.</p>
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